Using the model
Symbols, assumptions and limitations
Concentration values must describe one equilibrium state. Pure solids and pure liquids are omitted from equilibrium expressions. The numerical Kc–Kp conversion uses R = 0.082057 L·atm·mol⁻¹·K⁻¹ and the conventional textbook standard-state treatment.
Worked examples
See the method in practice
Hydrogen iodide formation
For H₂(g) + I₂(g) ⇌ 2HI(g), Kc = [HI]²/([H₂][I₂]) and Δng = 0, so Kp and Kc have the same numerical value.
Ammonia synthesis
For N₂(g) + 3H₂(g) ⇌ 2NH₃(g), Δng = 2 − 4 = −2; temperature therefore affects the numerical Kp/Kc conversion.
Questions
Frequently asked
What concentrations belong in Kc?
Use equilibrium molar concentrations, not initial concentrations, unless the reaction has not changed them.
Why are solids and liquids omitted?
Their activities are effectively constant in the usual ideal treatment and are absorbed into the equilibrium constant.
Does a large K mean a fast reaction?
No. K describes equilibrium composition and thermodynamic favorability, not how quickly equilibrium is reached.
Sources & review
Equations and examples are checked against the references below. Results are educational and should be independently verified for safety-critical work.
OpenStax Chemistry — Equilibrium ConstantsWritten by the STEM Hub editorial team · Reviewed August 11, 2026 · Review methodology